3x^2+36x=660

Solution for 3x^2+36x=660 equation:

3x^2+36x=660

We move all terms to the left:

3x^2+36x-(660)=0

a = 3; b = 36; c = -660;
Δ = b2-4ac
Δ = 362-4·3·(-660)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-96}{2*3}=\frac{-132}{6}
=-22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+96}{2*3}=\frac{60}{6}
=10
$